Question

Which graph shows the solution to the system of linear inequalities? y < 2x – 5 y > –3x + 1 On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded. Mark this and return

Answer 1

Answer:

See attachment

Step-by-step explanation:

To graph the inequality

$y$

We graph the dashed boundary line y=2x-5 with a positive slope of 2 and y-intercept (0,-5) and shade everything to the right.

To graph the inequality y>-3x+1, we graph the dashed boundary line y=-3x +1 with y-intercept (0,1) and shade every above it.

The intersection of the two shadings is the solution to the system of inequalities:

$y < 2x - 5$

and

$y > \: - 3x + 1$

See attached file.

Answer 2

Answer:

the answer is D simple

Step-by-step explanation: