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3 years ago

How does the division rule for exponents help in understanding why anything to the zero power is 1?

1 answer:

Nookie1986 [14]3 years ago

5 0

In the division rule you subtract the exponents when dividing numbers with the same base. One rule for exponents is that exponents add when you have the same base. This works for any number x that you want to plug in except for x = 0,because 0/0 is indeterminate (it is like dividing zero by zero). No matter what number we use when it is raised to the zero power it will always be 1.

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How much line of symmetry an square

zhenek [66]

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3 years ago

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PLEASE HURRYYYY

MariettaO [177]

The equations for the coordinates of the endpoint F should be x = 2 · 35 - 15 and y = 2 · (- 3) - 26.

<h3>How to derive the equations for the missing endpoint of a line segment</h3>

In this problem we know the coordinates of the endpoint E and the midpoint M of the line segment EF and we need to derive expressions of the coordinates of the endpoint F by the midpoint formula:

M(x, y) = 0.5 · E(x, y) + 0.5 · F(x, y)

2 · M(x, y) = E(x, y) + F(x, y)

F(x, y) = 2 · M(x, y) - E(x, y)

If we know that M(x, y) = (35, - 3) and E(x, y) = (15, 26), then the coordinates of the endpoint F are:

F(x, y) = 2 · (35, - 3) - (15, 26)

F(x, y) = (70, - 6) + (- 15, - 26)

F(x, y) = (55, - 32)

The equations should be x = 2 · 35 - 15 and y = 2 · (- 3) - 26.

To learn more on midpoints: brainly.com/question/8943202

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1 year ago

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What is the y intercept of the quadratic function f(x)=x^2+x-6

saveliy_v [14]

Answer:

$(0,\, -6)$ .

Step-by-step explanation:

On a cartesian plane, the $y$ -intercept of a function is the point where the graph of that function intersects with the $y\!$ -axis.

The $y$ -axis of a cartesian plane is the same as the equation $x = 0$ (that is, the collection of all points with an $x$ -coordinate of $0$ .)

Construct a system of two equations, with one equation representing $y$ -axis and $y = f(x)$ to represent the graph of this function:

$\begin{aligned}\begin{cases} y = x^{2} + x - 6 & \text{for the quadratic function} \\ x = 0 & \text{for the $y$-axis}\end{cases}\end{aligned}$ .

Solve this system for $x$ and for $y$ . If a solution exists, then the $y\!$ -axis and the graph of $y = f(x)$ would indeed intersect. The point $(x,\, y)$ would be the intersection of the $y\!\!$ -axis and the graph of $y = f(x)\!$ .

Substitute the second equation of the system into the first.

$\begin{aligned}\begin{cases} x = 0 \\ y = -6\end{cases}\end{aligned}$ .

Hence, the intersection of the $y$ -axis and the graph of $y = f(x)$ would be $(0,\, -6)$ . By definition, this point would be the $y\!$ -intercept of $y = f(x)\!$ .

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2 years ago

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Levart [38]

Step-by-step explanation:

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