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devlian [24]
3 years ago
8

In 1924, the temperature in Fairfield, Montana, dropped from 63 degrees to -21 degrees in 12 hours. What was the average hourly

change in temperature.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0
The average change hourly is 7 degrees per hour
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Y= x +2<br> x^2 +y^2=10<br><br> solve using any method
Jobisdone [24]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————- ★ ————-««  

Here’s why:  

  • I have graphed the two equations given on a graphing program.
  • When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
Read 2 more answers
You purchase two bottles of and a hat. The hat costs $6.50. You pay 6% sales tax. You pay a total of $16.43. How much does one b
Advocard [28]
$4.50.

Total with tax = 1.06x = 16.43
X = 15.50 = total before tax

15.50 - 6.50 = 9 = amount spent on both bottles.

9/2 = 4.5 = amount spent on one bottle.
8 0
3 years ago
Read 2 more answers
Complete the inequality statement <br><br> 7/10 ___ 11/20 <br><br> &gt; &lt; =
densk [106]
To start, give each fraction a common denominator by multiplying the 7/10 by two to get 14/20, an equivalent but not simplified fraction. now compare 14/20 and 11/20. 14/20 is greater than 11/20, so 7/10 > 11/20.
7 0
3 years ago
I need HELP PLSSSS , it’s hardd
MatroZZZ [7]
U can use math. way for this
6 0
2 years ago
Can anyone please help me with this attachment?
Vesna [10]

Answer:

Perimeter of the sector = (36 + 8π) cm.

Step-by-step explanation:

Formula to find the of an arc of the circle is,

Length of the arc = \frac{\theta}{360}(2\pi r)

Here, θ = central angle formed by the arc

r = radius of the circle

Therefore, length of the arc given in the picture = \frac{80}{360}(2\pi) (18)

                                                                                = 8π cm

Perimeter of the sector = Sum of all sides of the sector

                                       = Length of radius + length of the arc + length of radius

                                       = 18 + 8π + 18

                                       = (36 + 8π) cm

Perimeter of the sector is (36 + 8π) cm.

6 0
3 years ago
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