Answer:
Your teacher is right, there is not enough info
Step-by-step explanation:
<h3>Question 1</h3>
We can see that RS is divided by half
The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS
So P is not on the perpendicular bisector of RS
<h3>Question 2</h3>
We can see that PD⊥DE and PF⊥FE
There is no indication that PD = PF or ∠DEP ≅ FEP
So PE is not the angle bisector of ∠DEF
Answer:
x = 7
Step-by-step explanation:
The larger triangle is twice as big as the smaller triangle. Therefore, the length of the side EF is twice as large as the side YZ.
I multiplied 4.5 (the length of YZ) and 2 to get 9. The value of side EF is 3x-12 and should be equivalent to 9.
3x - 12 = 9
I solved this equation by adding 12 to both sides and dividing 3 on both sides.
The value of x is 7.
Katrina has read 85% of her book.
Answer:
![\boxed{\sf \ \ \ [-7,0] \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20%20%5B-7%2C0%5D%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
Hello
So values of x which is not in this domain is
which is [-7,0]
hope this helps
What is the lesson? We are aware that the 2 triangles are congruent, they also tell us what the two segments are equal to. Your best is to set up an equation making the segments equal to eachother to find the value of segment WK
