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Paladinen [302]

2 years ago

12

2.

1 answer:

AURORKA [14]2 years ago

5 0

Answer:

2. Ratio of 3/4

4. Ratio of 1/2

Step-by-step explanation:

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Agata [3.3K]

Answer:

16

Step-by-step explanation:

To start off this problem, we are given that the line AB is equal to the line CD. In addition to that, we are given that the line EF equally intersects line AB and line CD. This provides us proof that angle AGH is equivalent to angle DHG. From this information, we can solve this problem relatively easily.

Lets work with this equation:

$80 = 5x$

Next, divide 80 by 5.

$\frac{80}{5} =x$

$16 = x$

This means that x is equal to 16.

7 0

3 years ago

An alloy of silver and gold is to be recast with an addition of silver. This new alloy consists of 80 ounces and is to have only

Liula [17]

Answer:

What percentage of gold is in the new alloy after the recasting? 4

Step-by-step explanation:

(80/5)*(1/5)/80=0.04

5 0

3 years ago

Johnny Mac's sporting Goods bought a baseball glove from Rawlins sporting Goods for $66.00, They want to mark up the glove 70% o

lakkis [162]

The answer should be A, if he marked it up 70% just multiply 66 by 1.7 for your answer.

5 0

3 years ago

What is the correct ratio of each rational root of the polynomial Function

zimovet [89]

Answer:

factor of 6 and 5

Step-by-step explanation:

3 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

2 years ago