Help plz. What are the zeros of the function below? Check all that apply. (Picture is added)

Given that LM is a midsegment of IJK, find JK. A. 7 B. 8 C. 14 D. 16

Leno4ka [110]

Answer: Option D. 16

Solution:

If LM is a midsegment of IJK, it is joining the midpoint of the sides IJ and IK, and it's half the length of the base of the triangle (JK), then:

L is the midpoint of the side IJ, and divides it into two congruent parts:

IL=LJ

Replacing IL by 7x and LJ by 3x+4:

7x=3x+4

Solving for x: Subtracting 3x both sides of the equation:

7x-3x=3x+4-3x

Subtracting:

4x=4

Dividing both sides of the equation by 4:

4x/4=4/4

Dividing:

x=1

Then we can determine the length of LM:

LM=2x+6

Replacing x by 1 in the equation above:

LM=2(1)+6

LM=2+6

LM=8

and because LM is half the length of the base of the triangle (JK)

LM=(1/2) JK

Replacing LM by 8:

8=(1/2) JK

Multiplying both sides of the equation by 2:

2(8)=2(1/2) JK

16=(2/2) JK

16=(1) JK

16=JK

JK=16

8 0

4 years ago

Read 2 more answers

Olives garden is only 10 yd.² and the watermelon plants she wants to grow require 2.5 yd squared each how many watermelon plants

Ad libitum [116K]

Answer:

The answer is 4.

Step-by-step explanation:

Olives garden has area= $10 yd^2$

Each watermelon plants she want to grow require an area= $2.5 yd^2$

Hence, the number of watermelon plants she can grow in that garden is given by:

Number of watermelon plants she can grow= (Total area)/( Area 1 watermelon plant requires)

Hence, Number of watermelon plants she can grow= $\dfrac{10}{2.5}=4$

Hence, she can grow 4 watermelon plants in Olives garden.

7 0

3 years ago

prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

6 0

3 years ago

8 1/2 is to 17 as 17 11 1/2 is to 23

Stella [2.4K]

Hello from MrBillDoesMath!

Answer: Yes, (8 1/2) /`17 = ( 17 11/12) /23

** I think you meant 11 1/2 is to 23 NOT 17 11 1/2 is to 23"

Discussion:

First, 8 1/2 = 17/2 and

(17/2 ) / 17 = 1/2

Second 11 1/2 = 23/2 and

(23/2)/ 23 = 1/2

IN other words, the ratiors are the same:

8 1/2 11 1/2

------- = -------

17 23

Thank you,

MrB

5 0

4 years ago

Write x^2-12+19 in the form (x+a)^2+b

Westkost [7]

Answer:

(x-6)^2 -17

hope it helps

8 0

3 years ago