Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
(4,1), (-4,1), (4,6), (-4,6)
Step-by-step explanation:
Here can be identified two points with the same 'y' value: (4,1), (-4,1)
it means that there is a line passing by y=1
Same for (4,6), (-4,6): it means that there is a line passing by y=6
Now find the distance between two points in both cases
D is a function because there are no repeated x values
for example b is not a function because we have (0,-7) and (0,-9)
I hope this helps you
Brandon x
Michael 3x
18 years ago
Brandon x-18
Michael 3x-18
9 (x-18)=3x-18
9x-9.18=3x-18
9x-3x=9.18-18
6x=8.18
x=8.3
x= 24
Answer:
D. y-5 = 3(x+1)
Step-by-step explanation:
Slope of the perpendicular line is 3.
Slope intercept form is,
y-5 = 3 (x-(-1))
y-5 = 3(x+1)
