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Artyom0805 [142]
4 years ago
5

Vertex form of x^2+6x+3

Mathematics
1 answer:
Anastasy [175]4 years ago
8 0

Answer:

y = (x + 3)^2 - 6.

Step-by-step explanation:

The vertex formula is Y = a(x - h)^2 + k.

To find the vertex formula, we need to find h and k, by finding the vertex of x^2 + 6x + 3.

h = -b/2a

a = 1, b = 6.

h = -6 / 2 * 1 = -6 / 2 = -3

k = (-3)^2 + 6(-3) + 3 = 9 - 18 + 3 = -9 + 3 = -6

So far, we have Y = a(x - (-3))^2 + -6, so y = a(x + 3)^2 - 6.

In this case, the coefficient of x^2 of the given formula is 1, which means that a will be 1.

The vertex form of x^2 + 6x + 3 is y = (x + 3)^2 - 6.

To check our work...

y = (x + 3)^2 - 6

= x^2 + 3x + 3x + 9 - 6

= x^2 + 6x + 3

Hope this helps!

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Answer:

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Step-by-step explanation:

you make everything an improper fraction then times it

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Wendy's restaurant has been recognized for having the fastest average service time among fast food restaurants. In a benchmark s
VikaD [51]

Answer:

(a) 0.2885

(b) 0.0736

(c) 0.0468

Step-by-step explanation:

The exponential distribution of Wendy's service time is given by:

P(x) =  [exp (-x/μ)]/μ............................................................................ (1)

P(x) = Probability function

x = Service time, in minute

μ = average service team, in minute, 2.2 minutes

(a) x= 1, substituting into equation (1) we have:

P(1) =  [exp (-1/2.2)]/2.2

     = 0.6347/2.2

     =  0.2885

(b)  x₁ = 0.5 minutes

       x₂ = 1 minute

P (0.5<x<1) = P(0.5) -P(1) ----------------------------------------------- (2)

From (a), P (1) =  0.2885

P(0.5) =P(1) =  [exp (-0.5/2.2)]/2.2

     = 0.7967/2.2

     =  0.3621

Substituting into (2), we have :

P (0.5<x<1) = 0.3621 -0.2885

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ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

max accepts two int arguments and returns the value of the larger one:

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Four int variables, population1, population2, population3, and population4

max (population1, population2) ⇒ return the larger one between population1 and population2

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An expression whose value is the largest of population1, population2, population3, and population4 by calling max is:

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