Find a common multiplier between both which would be 4. then divide each term by 4. all you have left stays in the parenthesees.
4 (2x+5)
Answer:
EF = 6.6
Step-by-step explanation:
Since ABCD is similar to EFGH, then EH is similar to AD. So, we can solve by first dividing 12 by 2 (EH by AD). The quotient of this is 6. This tells us that quadrilateral EFGH is 6 times larger than quadrilateral ABCD, since they are similar. So, with this and the measurement of AB (which is similar to EF), we can now solve for EF. We simply multiply 1.1 (the measurement of AB) by 6 (how many times larger EFGH is compared to ABCD). The product of this is 6.6, our final answer.
Hello.
C) x=4π/3
The variable x in the cotangent argument has a unit coefficient, so the period is π, just as it is in the parent function cot(x).
Can you graph y = cot(x)? By subtracting the constant π/6 from the argument, that graph is translated to the right by π/6. Just as with cot(x), it is decreasing everywhere.
Have a nice day
Answer:
The first plant produces 2x + 21 more items daily than the second plant.
Step-by-step explanation:
The daily production of the two plants are:
Plant 1: 5x + 14
Plant 2: 3x - 7
Compute the number of items first plant produces more than the second plant as follows:
Thus, the first plant produces 2x + 21 more items daily than the second plant.
