Question

Please i beg for help !!!!!!!!!!! will mark brainlist

Answer 1

Answer:

$x=-10$

Step-by-step explanation:

This deals with negative exponents.

$x^{-2}=\frac{1}{x^2}$

27 and 9 are both powers of 3, so we need to find a way to make both of these into a base 3.

9 is easy, thats just:

$9=3\times3=3^2$

1/27 is a little more difficult. Start with 27:

$27=9\times3=3\times3\times3=3^3$

and because its a 1/27, that exponent has to be negative.

$3^3=27\\3^-^3=\frac{1}{27}$

Now we can get both of them to base 3, so do that in the given equation:

$3^{(-3)\times(4-x)}=3^{(2)\times(2x-1)}$

Same as last time, the bases can be canceled out as the exponents have to be equal for this equation to be true.

$3^{(-3)\times(4-x)}=3^{(2)\times(2x-1)}\\(-3)\times(4-x)=(2)\times(2x-1)$

Finally, solve for x:

$-3(4-x)=2(2x-1)\\-12+3x=4x-2\\-10+3x=4x\\x=-10$