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DerKrebs [107]
3 years ago
15

There are 20 members of a basketball team.

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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Is it true or false that the measure of A is 45°
GrogVix [38]
The answer is false
8 0
3 years ago
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
Helen wrote and solved the equation.
Savatey [412]

Answer:

b, Helen should have added 17 to both sides of the equation

Step-by-step explanation:

just took quiz and got it right so it will help u guys too.!!!

7 0
2 years ago
Read 2 more answers
Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​
d1i1m1o1n [39]

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle .

4 0
2 years ago
Read 2 more answers
Show all work to factor x4 – 17x2 + 16 completely.
denis23 [38]

Answer:

(x - 4)(x + 4)(x - 1)(x + 1)

Step-by-step explanation:

Given

x^{4} - 17x² + 16

Use the substitution u = x², then

u² - 17u + 16

Consider the factors of the constant term (+ 16) which sum to give the coefficient of the u- term (- 17)

The factors are - 16 and - 1, then

u² - 17u + 16

= (u - 16)(u - 1) ← replace u by x²

= (x² - 16)(x² - 1) ← both factors are difference of squares

= (x - 4)(x + 4)(x - 1)(x + 1)

4 0
2 years ago
Read 2 more answers
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