Question

The number of wins and losses of two local basketball teams are shown in the table. Find the probability that a randomly selected game from the season was played by the wolves, given that it was a loss.
----inserted table-----
wins Losses
Wolves 18 12
Hawks 14 16

Answer choices---
0.533
0.200
0.429
0.400

Answer 1

Answer: 0.429

Step-by-step explanation:

From the given table, the total number of games were loss = 12+16=28

The number of games was played by the wolves and was a loss = 12

The total number of games played  = 18+12+16+14=60

Now, the probability of games was played by the wolves and was a loss is given by ;-

$\text{P(wolf and loss)}=\dfrac{12}{60}=\dfrac{1}{5}$

The probability of games that were loss is given by :-

$\text{P(loss)}=\dfrac{28}{60}=\dfrac{7}{15}$

Now, the probability that a randomly selected game from the season was played by the wolves, given that it was a loss is given by :-

$=\dfrac{\text{P(wolf and loss)}}{\text{P(loss)}}\\\\=\dfrac{\dfrac{1}{5}}{\dfrac{7}{15}}\\\\\\=\dfrac{3}{7}=0.428571428571\approx0.429$

Answer 2

Answer:

Step-by-step explanation:

it is c good luck on the rest of your test