Help please :) I will show the next questions in the other one so please answer them.

horsena [70]

x | y
——-
-10|-18
-9 |-17
-8 |-16
-7 |-15
-6 |-14
-5 |-13
-4 |-12
-3 |-11
-2|-10
-1 | -9
0 | -8
1 | -7
2 |-6
3 | -5
4 | -4
5 | -3
6 | -2
7 | -1
8 | 0
9 | 1
10| 2

6 0

3 years ago

Read 2 more answers

The quotient of two less than a number and five is eight

postnew [5]

Answer:

The number is 42.

Step-by-step explanation:

Let x be the unknown number.

"two less than a number" is x - 2

Quotient means the result of a division.

(x - 2)/5 = 8

Multiply both sides by 5.

x - 2 = 40

Add 2 to both sides.

x = 42

Answer: The number is 42.

Check.

Start with 42. 2 less than 42 is 40. The quotient of 40 and 5 is 40/5 which is 8. The answer is correct.

5 0

2 years ago

Which set of numbers does -5 belong

tester [92]

Is there any more to this question? Because-5 doesn’t belong anywhere

3 0

2 years ago

» Alexander has some watermelons. He gathers 13 more watermelons. He now has 62 watermelons.

Vilka [71]

Yeah but what is the question?

3 0

2 years ago

For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x

Alla [95]

The correct answer is:

D) $\left \{ {{2x-y=7} \atop {2x+7y=31}} \right.$ .

Explanation:

We solve each system to find the correct answer.

For A:
$\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.$

Since we have the coefficients of both variables the same, we will use elimination to solve this.

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
$\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. 
\\
\\6x=23$

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is not the x-coordinate of the answer we are looking for, so A is not correct.

For B:
$\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.$

For this equation, it will be easier to isolate a variable and use substitution, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is not the y-coordinate of the answer we're looking for, so B is not correct.

For C:
Since the coefficient of x in the second equation is 1, we will use substitution again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is not the y-coordinate of the answer we're looking for, so C is not correct.

For D:
Since the coefficients of x are the same in each equation, we will use elimination. We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

$\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. 
\\
\\-8y=-24$

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so D is the correct answer.

7 0

3 years ago