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Rama09 [41]
3 years ago
14

20 is what percent of 50

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0
The answer to the equation is 30%
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Find equation of vertical line through (-5, -3)
Novay_Z [31]

Answer:

x = -5

Step-by-step explanation:

Given that it is a vertical line, we know that it will only go through one x-value.

We are also given a point, (-5, -3).

This point tells us that the vertical line only goes through the x-value -5, so the equation will be x = -5.

5 0
4 years ago
In a survey, a group of students were asked their favorite sport. Eighteen students chose “other” sports, while 37.5% chose foot
Leno4ka [110]

Answer:


It would be 6.75%

Step-by-step explanation:

Because, if you divide 18 by 37.5%, you will get you answer (6.75%)

3 0
4 years ago
Please answer this i need to pass
Anon25 [30]

Answer: 88/102

Step-by-step explanation: I think it's 88/102

6 0
3 years ago
Read 2 more answers
How would you solve for this problem. The line is parallel to the line y=1/2x +5 and passes through (2,-5).
zaharov [31]

Answer:

is 5.8

Step-by-step explanation:

i do it in a calculador so is 5.5

3 0
3 years ago
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Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo
Anna11 [10]

I'll assume you're supposed to compute the line integral of \nabla f over the given path C. By the fundamental theorem of calculus,

\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)

so evaluating the integral is as simple as evaluting f at the endpoints of C. But first we need to determine f given its gradient.

We have

\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)

Differentiating with respect to y gives

\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C

and we end up with

f(x,y)=-3\cos(xy)+C

for some constant C. Then the value of the line integral is -3\cos192+3\cos3.

8 0
4 years ago
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