The numbers are 5 and 12.
Smaller number = x
Larger number = y
x +y =17
y = 3x - 3
x +3x -3 = 17
4x = 20
x = 5
smaller number is 5
y = 3(5) - 3
y = 12
larger number is 12.
To solve this problem,you need to use the formula d = rd (distance = rates x time)She runs at a speed of 7 mph and walks at a speed of 3 mph. Her distance running is d = 7trwhere tr is the time she spends running Her distance walking isd = 3twwhere tw is the time she spends walking The distances are the same so7tr = 3tw We also know that the total time is 4 hourstr + tw = 4tr = 4-tw Substitute this value of tr in the first equation7tr = 3tw7(4-tw) = 3tw28-7tw = 3tw28 = 10tw2.8 = tw Denise will spend 2.8 hours (2 hours, 48 minutes) walking back and 1.2 hours (1 hour, 12 minutes running.
Hope I helped :)
5% of 235 is: 235*(5/100)= 235/20 = 11,75 or 5% of 470 is: 470/20 = 23,5
Total cost = 2*(235 + 11,75) = 2*246,75 = 493,5 or Total cost = 470 + 23,5 = 493,5
Answer:
→ The table is:
→ x → -1 → 0 → 1
→ y → -3 → 0 → 3
The graph of the line is figure d
Step-by-step explanation:
∵ y = 3x
∵ x = -1, 0, 1
→ Substitute the values of x in the equation to find the values of y
∴ y = 3(-1) = -3
∴ y = 3(0) = 0
∴ y = 3(1) = 3
→ The table is:
→ x → -1 → 0 → 1
→ y → -3 → 0 → 3
∵ The form of the linear equation is y = m x + b, where
∵ y = 3x
→ Compare the equation with the form
∴ m = 3
∴ b = 0
→ That means the slope is positive, then the direction of the line must
be from left tp right and passes through the origin
∴ The graph of the line is figure d
1. Rational/The sum of two rationals is always rational
2. Irrational/ the sum of a rational and an irrational is always irrational
3. Irrational/The product of a nonzero rational and an irrational is always irrational
4. Rational/The product of two rationals is always rational
Pretty much all the irrational numbers are the ones with radical signs over them and the rational numbers are the fractions and whole numbers. Once you identify the two numbers to be rational or irrational, you can then find your answer within the second part of the answers.