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2 years ago

How do I reflect over x=3 ??

1 answer:

3 0

This last claim is because x can be thought of as 2+a, where "a" could be negative! Now x needs to go to 2-a, but solveing for "a" in x=2+a gives a=x-2, so the new x is
2-a = 2-(x-2) = 4-x. 

(-1,1) => (5,1) 
(0,4) => (4,4) 
(-3,4) => (7,4)

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What is the value of f(-3)

Readme [11.4K]

$f(x)=\left\{\begin{array}{ccc}-2&if&x < -3\\4x&if&-3\leq x\leq-1\\x^2&if&x > -1\end{array}\right\\\\-3\leq-3\leq-1\to f(x)=4x\\\\f(-3)=4(-3)=-12$

8 0

3 years ago

What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?

sergeinik [125]

If they are parallel then the coefficients of x and y will remain the same. Only the constant will change.

2x + 3y = ?
2(-2) +3(3) = -4 + 9 = 5 so ? is 5

ANSWER: 2x + 3y = 5

6 0

2 years ago

Could someone answer and explain these please? Thank you!

Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

$x=(10 \times t)+(1 \times u)$

$x=10t+u$

The two digit number 'y' is obtained by reversing the digits of x.

So, $y=(10 \times u)+(1 \times t)$

$y=10u+t$

Now, the value of x-y is expressed as:

$x-y=(10t+u)-(10u+t)$

$x-y=10t+u-10u-t$

$x-y=9t-9u$

$x-y=9(t-u)$

So, $9(t-u)$ is equivalent to (x-y).

Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = $\frac{a}{1-r}$

Since, the sum of the given infinite geometric series = 200

Therefore, $\frac{a}{1-r}=200$

Since, r=0.15 (given)

$\frac{a}{1-0.15}=200$

$\frac{a}{0.85}=200$

$a=0.85 \times 200$

a=170

The nth term of geometric series is given by $ar^{n-1}$ .

So, second term of the series = $ar^{2-1}$ = ar

Second term = $170 \times 0.15$

= 25.5

So, the second term of the geometric series is 25.5

Step-by-step explanation:

8 0

3 years ago

Covert (3×10²)(2×10³) to scientific notation. Show work please.

leonid [27]

(3*2)(10^2 * 10^3) = 6*10^5

4 0

3 years ago

A large company wanted to know how the average salary of their employees had changed over the last year. the results of their st

Aleksandr-060686 [28]

A large company wanted to know how the average salary of their employees had changed over the last year. the results of their study had a p-value of 0.12and showed that the average salary had increased by $1,500 from $20,000 to $21,500. The results were practically significant but not statistically significant.

4 0

2 years ago