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Mumz [18]
3 years ago
14

How do I reflect over x=3 ??

Mathematics
1 answer:
Contact [7]3 years ago
3 0
This last claim is because x can be thought of as 2+a, where "a" could be negative! Now x needs to go to 2-a, but solveing for "a" in x=2+a gives a=x-2, so the new x is 
<span>2-a = 2-(x-2) = 4-x. </span>



<span>(-1,1) => (5,1) </span>
<span>(0,4) => (4,4) </span>
<span>(-3,4) => (7,4)</span>
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