What is the pattern 3 6.5 11 16.5 23

If the mean of a symmetric distribution is 75, which of these values is most likely to be the median of the distribution????????

AlekseyPX

B. 75.

Explanation: You're more likely to get 75 as the answer because it's in the middle of the symmetric distribution. The equation for the mean average is
sum of all numbers / how many number there are. And at the middle is where all the averages are.

7 0

4 years ago

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When the Bucks play Chiefs at football, the probability that the Chiefs, on present form, will win is 0.56. In a competition, th

Tom [10]

Answer:

The probability that Swallows will win the trophy is 0.8064

The probability that Rucks will win the trophy is 0.1936

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the Swallows win, or they do not. The probability of them winning a game is independent of any other game, which means that the binomial probability distribution is used.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability the Swallows wins is 0.56

This means that $p = 0.56$

2 games:

This means that $n = 2$

The probability that Swallows will win the trophy is

Probability they win at least one game, so:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.56)^{0}.(0.44)^{2} = 0.1936$

Then

$P(X \geq 1) = 1 - 0.1936 = 0.8064$

0.8064 = 80.64% probability the Swallows win the trophy and 0.1936 probability that the Rucks win the trophy.

5 0

3 years ago

a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample s

Alex

Answer:

95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

Step-by-step explanation:

We are given that a consumer magazine counts the number of tissues per box in a random sample of 15 boxes of No- Rasp facial tissues. The sample standard deviation of the number of tissues per box is 97.

Firstly, the pivotal quantity for 95% confidence interval for the population variance is given by;

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2}__n_-_1$

where, $s^{2}$ = sample variance = $97^{2}$ = 9409

n = sample of boxes = 15

$\sigma^{2}$ = population variance

Here for constructing 95% confidence interval we have used chi-square test statistics.

So, 95% confidence interval for the population variance, $\sigma^{2}$ is ;

P(5.629 < $\chi^{2}__1_4$ < 26.12) = 0.95 {As the critical value of chi-square at 14

degree of freedom are 5.629 & 26.12}

P(5.629 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 26.12) = 0.95

P( $\frac{5.629 }{(n-1)s^{2} }$ < $\frac{1}{\sigma^{2} }$ < $\frac{26.12 }{(n-1)s^{2} }$ ) = 0.95

P( $\frac{(n-1)s^{2} }{26.12 }$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{5.629 }$ ) = 0.95

95% confidence interval for $\sigma^{2}$ = [ $\frac{(n-1)s^{2} }{26.12 }$ , $\frac{(n-1)s^{2} }{5.629 }$ ]

= [ $\frac{14 \times 9409 }{26.12 }$ , $\frac{14 \times 9409 }{5.629 }$ ]

= [5043.11 , 23401.31]

Therefore, 95% confidence interval for the population variance of the number of tissues per box is [5043.11 , 23401.31].

6 0

4 years ago

How would I graph y=2x-2; domain: x>0

stira [4]

Hello,

Please find below the graph you need.

For x = 0, f(0) = --2, then for x = 1, f(1) = 0, graph is a straight line, you just need to draw that line through points (0, --2) and (1, 0), as simple as that, see below.

Green eyes.

8 0

3 years ago

Kathy is baking cakes each cake requires 1/12 of a teaspoon of vanilla and she has 9/12 of a teaspoon how many cakes can she bak

masya89 [10]

Kathy can make 9 cakes

8 0

3 years ago

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