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sergij07 [2.7K]
3 years ago
15

What is the axis of symmetry, vertex and y intercept for 2x^2-8x-5

Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

Axis of symmetry: x = 2

Vertex at: (2, -13)

y-intercept is (0, -5)

Step-by-step explanation:

The equation for the x-value of the vertex in a quadratic of the form:

y=ax^2+bx+c

is given by:

x_{vert}=-\frac{b}{2\,a}

which in our case gives:

x_{vert}=\frac{8}{2*2} =2

Then the equation for the axis of symmetry is given by:  x = 2

and the y of the vertex can be calculated as:

y_{vert}=2 (2)^2-8\,(2)-5=-13

Then the vertex is at the point: (2, -13)

And the y-intercept is found when x=0, that is:

y-intercept is (0, -5)

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HELP ASAP
denis-greek [22]
A) I included a graph, look below.

B)

Input the y in x = y + 3.

x = (-4x - 3) + 3
x = -4x + 0
Add 4x to both sides.
5x = 0
Divide both sides by 5.
x = 0

Input that x value in y = -4x - 3

y = -4(0) - 3
y = 0 - 3
y = -3

(0, -3)

C)

Convert both equations to Standard Form.

x = y + 3
Subtract y from both sides.
x - y = 3

y = -4x - 3
Add 4x to both sides.
4x + y = -3

Add the equations together.

4x + y = -3
x - y = 3
equals
5x = 0
Divide both sides by 5.
x = 0

Input that into one of the original equations.

0 = y + 3
Subtract 3 from both sides.
-3 = y

(0, -3)

7 0
3 years ago
Y=x²-6x+8 what is y when x is 0?
jarptica [38.1K]

Answer:

The value of y is 8.

Step-by-step explanation:

In order to find the value of y, you have to put in x = 0 into the equation :

y =  {x}^{2}  - 6x + 8

Let x = 0,

y =  {0}^{2}  - 6(0) + 8

y = 8

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3 years ago
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elena55 [62]

Answer:

I got 18.26

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
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Natalka [10]

Answer:

-50

Step-by-step explanation:

b-5 \geq -45

b-5 = -45 ( collect like terms)

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2 years ago
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