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2 years ago

I need help with this question.

Mathematics

1 answer:

Zinaida [17]2 years ago

8 0

Answer:

smallest value of x = -6

Largest value of x= 6

Step-by-step explanation:

Set equal then factor

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What is x?<br> HELP!!<br> Pls

kow [346]

Since line c and d are parallel, line a can act as a transversal. Thus, x=124 degrees because of the alternate exterior angle relationship that can be seen.

7 0

2 years ago

Read 2 more answers

Determine which system of equation has (-3,19) and (4,-23) as a solution?

grandymaker [24]

Answer:

y=6x+1

Step-by-step explanation:

First you must find the slope of the two points...

$\frac{4--3}{-23-19}$ which then would equal 6

Then you take the slope and put into point-slope form

(y-y1)=m(x-x1)...take one of the points that is given and plug it into this formula.

so I used (-3,19).

(y-19)=6(x--3)

I would then get y-19=6x+18

Add 19 to both sides and you will get y=6x+1

4 0

2 years ago

PLS HELP 20 POINTS!!

Nitella [24]

Answer:

1. 144km

2. 96 km

3. 200 km

Step-by-step explanation:

see image

5 0

1 year ago

Read 2 more answers

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

2 years ago

What is the volume of a cone that has a radius of 12 m and a height of 3 m?

vfiekz [6]

452.16 m^3
1/3 = 0.333333333
0.333333333 * 3.14 = 1.046666667
1.046666667 * 144 =150.72
150.72 * 3 = 452.16

5 0

2 years ago

I need help with this question. ​

I need help with this question.