Solve for e: E=〖mc〗^2 M = 3 C = 6

Find the inverse of g(x) = 3x^2 - 5

Lorico [155]

Answer:

x

=

√

y

+

5

3

Explanation:

To find the inverse of a function expressed as

XXX

y

=

an expression in

x

rearrange the expression into the form:

XXX

x

=

an expression in

y

Given

XXX

y

=

3

x

2

−

5

Switch sides and add

5

to both sides

XXX

3

x

2

=

y

+

5

Divide both sides by

3

XXX

x

2

=

y

+

5

3

Take the square root of both sides

XXX

x

=

±

√

y

+

5

3

Since we were asked for an inverse function, I've eliminated the non-primary root (a function can not have two values for a single argument value).

Therefore

XXX

x

=

instead of Y do G

Step-by-step explanation:

4 0

3 years ago

QUESTION Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm.

STALIN [3.7K]

4.3 bc it’s right and i did the assignment

5 0

3 years ago

What is the answer To 1/2 + 1 3/4

Bogdan [553]

1. 1/2+13/4=14/6 ответ

4 0

3 years ago

80:(8+2)<br><br>a. 12<br>b. 11<br>c. 1

german

I think something is not right here, the answer supposed to be 8

6 0

3 years ago

Read 2 more answers

(Uniform) Suppose X follows a continuous uniform distribution from 4 to 11. (a) Write down the PDF of X. (b) Find P(X ≤ 7). Roun

love history [14]

Answer:

a) $f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

b) $P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

c) $P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

d) $P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

Step-by-step explanation:

For this case we assume that the random variable X follows this distribution:

$X \sim Unif (a=4, b =11)$

Part a

The probability density function is given by the following expression:

$f(x) = \frac{1}{b-a} , a \leq x \leq b$

$f(x)= \frac{1}{11-4}= \frac{1}{7}, 4 \leq x \leq 11$

Part b

We want this probability:

$P(X \leq 7)$

And we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a}= \frac{x-4}{11-4}$

And replacing we got:

$P(X\leq 7) = F(7) = \frac{7-4}{11-4}= 0.4286$

Part c

We want this probability:

$P(5 < X \leq 7)$

And we can use the CDF again and we have:

$P(5 < X \leq 7)= F(7) -F(5) = \frac{7-4}{7} -\frac{5-4}{7}= 0.2857$

Part d

We want this conditional probabilty:

$P(X >5 | X \leq 7)$

And we can find this probability with this formula from the Bayes theorem:

$P(X >5 | X \leq 7)= \frac{P(X>5 \cap X \leq 7)}{P(X \leq 7)}= \frac{P(5$

7 0

3 years ago