Answer:
I believe its -68 but i could be wrong, because that's not a rational number, but it could also be -4080/60
<u>44%</u>
Sample space is 36C4
Now, we want to know all of the combinations that have 1 digit in it.
So, we can have one here:
1XXX
X1XX
XX1X
XXX1
But we have 10 different digits to choose from. So, we need to introduce the combination term, nCr, where n is a list of all digits and r is how many we want.
Since we only want one, we will need 10C1 for the number of digits. But we need to choose three lowercases, so it becomes 10C1 × 26C3
Since it's a probability question, we need to divide that by our sample space, 36C4, and our percentage becomes 44%
Answer:
1, 2, and 6
Step-by-step explanation:
5*.25=1.25 7*.25=1.75 12*.25=3
<span>So
let’s simplify the given situation.
We need to find out how much heavier is 91/8 lbs. compare to 2 5/6 lbs.
Since, it’s a combination of whole number and fraction; we cannot directly
subtract this given equation. We need to convert the two given number into a
fraction.
9 1/8 = 8 x 9 = 72 + 1 = 73, 73 is our numerator and 8 is our denominator
=> 73/8
2 5/6 = 6 x 2 = 12 + 5 = 17, 17 is our numerator and 6 is our denominator
=> 17/6
Now, we have 2 fractions with unlike denominator. In order to get a common
denominator, we have to find their least common factor.
=> <u>73</u> - <u>17 </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
</u> 8 6
8 x 6 6
x 8</span><span>
=> <u>438</u> – <u>136 </u> Now, we
have the same denominator, subtract</span><span>
48 48
=> <u>302 </u> or <u>151</u>
48 24
=> 6 <u>7</u>
24
Therefore 9 1/8 lbs. is 6 7/24 lbs. heavier than 2 5/6 lbs.</span>
