Ask question

Ask question

All categories

2 years ago

15

Consider the trinomial 6x2 + 13x + 6.

2 answers:

svetoff [14.1K]2 years ago

10 0

the value of ac is 36

the value of b is 13

the two numbers that have a product of ac and a sum of a and b are 4 and 9

attashe74 [19]2 years ago

8 0

In the given expression 6X² + 13X +6, we can easily identify the values of a, b and c. These values are a=6, b=13 and c=6
For the value of "ac", we have:
ac=6*6
ac=36
For a sum of b are 4, we have
ac+b=36+13=49
Therefore, the answer for the last question "The two numbers that have a product of ac and a sum of b are 4 and 9".

You might be interested in

Please help me with this...it’s 2am and I still have 3 more assignments...thank you

BARSIC [14]

Answer:

maybe y= 9 because side A B is 10 and side C D is almost the same just sleep slightly shorter.

3 0

2 years ago

Read 2 more answers

Adrian increased the amount of water he drinks he drinks everyday from 32 oz to 56 oz.By what percentage the amount of water he

Svetradugi [14.3K]

You can ask Siri. Answer is Increased 75%. “What percent is 56 out of 32.”

8 0

2 years ago

I need to know what the sum of 347.89 + 23.52!!!

vodomira [7]

Answer:371.41

Step-by-step explanation:

this is because you just need to carry the number over to the next place if the sum of the digits( example 8+9=17) if it is greater than 10

5 0

3 years ago

Read 2 more answers

Ahmed is taking orders for lunch. A slice of pizza cost $2.1 and a chicken sandwich costs $3.1. He collects $22.8 for the group

noname [10]

X=2
y=6

x+y=8
2.1x+3.1y=22.8

7 0

2 years ago

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

S_A_V [24]

Answer:

Required,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

Step-by-step explanation:

Given volume and depth respectively,

$V(x)=x^3+13x-210$ and $x-3$

To find length and width of the rectanglular swiming pool we know,

Volume=length $\times$ height $\times$ depth.

Let depth=D=x-3, length=L, width=W, then

$V=DLW$

$x^3+13x-210= LW(x-3)$

$LW=\frac{x^3+13x-210}{x-3}$

After divide we will get $x^2-3x-22$ with remainder -144.

Thus,

$x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW$

Now to find root of,

$x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}$

Thus,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

5 0

2 years ago