Answer:
30.49 m
Step-by-step explanation:
To obtain the maximum height, we solve for the value x when dy/dx = 0.
Since, y = -5x² + 40x + 20
dy/dx = d[-5x² + 40x + 20]/dx
dy/dx = -10x + 40
Since dy/dx = 0,
-10x + 40 = 0
-10x = -40
x = -40/-10
x = 4
Substituting x = 4 into the equation for y, we have
y = -5x² + 40x + 20
y = -5(4)² + 40(4) + 20
y = -5(16) + 160 + 20
y = -80 + 160 + 20
y = 80 + 20
y = 100 ft
Since y is in feet, we convert to meters.
Since 1 m = 3.28 ft, 100 ft = 100 ft × 1 m/3.28 ft = 30.49 m
So, the maximum height, in meters reached by the projectile is 30.49 m
Answer:
3 sets.
1 7 10
2 7 9
3 7 8.
Step-by-step explanation:
The sum must be 18 ( 3*6) and 7 is the middle number ( the median).
So the first and last numbers must add up to 11 with the first number less than 7. As there is no mode no number can be repeated.
So one set is 3 7 8 (the first number can't be 4 as the last number would have to be 7)
Others are 2 7 9,
1 7 10.
Answer:
agree
Step-by-step explanation:
Answer:
A. n = -2
Step-by-step explanation:
A. n = -2
4(-2) + 9 = 1
-8 + 9 = 1
1 = 1
