Answer:
<u>Undecillion</u> has 36 0's
Answer:
55
Step-by-step explanation:
bc
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
(9 - 7 X 3 + 4 )²
Always follow the rule
BIDMAS
Brackets
Indices
Division
Multiplication
Addition
Subtraction
First look at the Brackets
There are no indices in the brackets
There is no division in the brackets
There is a Multiplication in the brackets 7 x 3
For the answer
(9 - 7 x 3 + 4)²
Brackets
Multiplication 7 x 3 = 21
(9 - 21 + 4)²
Addition -21 + 4 = -17
(9 - 17)²
Subtraction 9 - 17 = -8
-8²
Now start again once the brackets are gone
-8²
Indices
-8 x -8 = 64
Answer:
Option (B)
Step-by-step explanation:
From the graph attached,
There are two functions graphed,
y = f(x) and y = h(x)
h(1) = 0 [Output value of function 'h' at the input value x = 1]
Since, g[h(1)] = g(0)
Therefore, value of function 'h' (output value) at (input value) x = 0,
g(0) = -5
Option B will be the correct option.
