Given:
plot of land doubles in size.
original plot area 200 by 300 meters
Area = 200m * 300m
A = 60,000 m² original plot area
60,000m² x 2 = 120,000 m²
(200m + x)(300m + x) = 120,000 m²
60,000m² + 200m*x + 300m * x + x² = 120,000 m²
x² + 500x + 60,000 = 120,000
x² + 500x + 60,000 - 120,000 = 0
x² + 500x - 60,000 = 0
x = -b <u>+</u> (√b² - 4ac)/2a
a = 1 ; b = 500 ; c = -60,000
x = -500 + (√500² - 4(1)(-60,000)) / 2(1)
x = (-500 + (√250,000 + 240,000)) / 2
x = (-500 + 700)/ 2
x = 200 / 2
x = 100 meters
(200 + x)(300 + x) = 120,000
(200 + 100)(300 + 100) = 120,000
300 * 400 = 120,000
120,000 = 120,000
ANSWER: -252
HOW TO GET IT:
Simply follow PEMDAS. Solve each exponent first, then do the rest.
Answer:
Step-by-step explanation:
The computation of the number of acres of land does the farmer owns is as follows:
Given that
the land of the farmer would be separated into size of 
acres
And, the sections would be 
So,
The number of acres would be
Now just multiply the denominator and numerator straight across
X + x + 2 = 14
2x + 2 = 14
2x = 12, x = 6
Solution: the smallest of the two integers is 6
