3 years ago

PLEASE CHECK MY ANSWERS (PART 1)

Mathematics

2 answers:

Tpy6a [65]3 years ago

8 0

You're smart! You don't need us checking your work. They are correct anyway

andrezito [222]3 years ago

7 0

All of you answers are correct. Great job! But it is always good to check answers!

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(a + b)(a ² - ab + b ²) Please help!

kvasek [131]

Hey there :)

( a + b )( a² - ab + b² )
Let us distribute ( a + b )

a ( a² ) + a ( - ab ) + a ( b² ) + b ( a² ) + b ( - ab ) + b ( b² )
a³ - a²b + ab² + a²b - ab² + b³

We can simplify further:
- a²b + a²b = 0
ab² - ab² = 0

a³ + b³

You can see in the picture I have attached that this is the 7th formula

4 0

3 years ago

Read 2 more answers

Let x and y be independent each uniformly distributed on {1,2,...,n} find p(x < y )

bulgar [2K]

If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y

y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =

We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)

However, if the sample space is continuous, it will be simply p(x<y)=1/2.

8 0

2 years ago

Hi, so i have a question and i'm giving away free points so here's the question! If you answer ill put out another question and

Shtirlitz [24]

Answer:

1. Saturday

2(a) 10,944

2(b) 32700

3. (16,24)

Step-by-step explanation:

8 0

3 years ago