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4 years ago

HELP PLEASE! ASAP! Please write a response. No bad laughuag

Mathematics

2 answers:

Vedmedyk [2.9K]4 years ago

7 0

Only a immature fool would laugh at someone asking for help.

see how x goes up one (the top one)

y goes up? 0.8

so the next is 6.2 and 7.0

Likurg_2 [28]4 years ago

5 0

Answer:

The common difference is 0.8, and the two missing b values are 6.2 and 7.0.

Step-by-step explanation:

Focus on the 2nd row of the table first. Determine the common difference. Starting with 3.8 and moving to the right, the next b value is 4.6 (an increase of 0.8 from 3.8) and the next one after that is 5.4 (also an increase of 0.8 from the previous b vaue). So the common difference is 0.8.

Add 0.8 to b=5.4; we get 6.2. Add 0.8 to b = 6.2; we get 7.0. So the two missing values in the 2nd row of the table are 6.2 and 7.0.

This is an example of what it means to discover a "pattern" or "rule."

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6. Three bunches of flowers can be bought for $9.48. Four bunches can be bought for $10.64. Which is the better buy?

lawyer [7]

The better buy would be four bunches for $10.66 because each bunch of flowers would be $2.66 compared to $3.16 per bunch.

5 0

3 years ago

B. Does a12 x a4 = a8 x a8 for all values of a? Explain.

sweet-ann [11.9K]

Answer:

We can use the Laws of Exponent to rewrite both sides of the equation:

Let a¹² x a⁴ = a⁸ x a⁸

⇒ a¹²⁺⁴ = a⁸⁺⁸

a¹⁶ = a¹⁶ ✅

⇒ a¹² x a⁴ = a⁸ x a⁸ is true for all values of a.

Explanation:

The equation a¹² x a⁴ = a⁸ x a⁸ is true because, on both the RHS and LHS of the equation, both terms in 'a' have exponents that when added (Law of Multiplication of Exponents) are equal to each other, i.e. 12+4 = 8 + 8.

3 0

3 years ago

Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter

jolli1 [7]

Answer:

the answer is incomplete, below is the complete question

"Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3ti + (1 - 4t)j + (1 + 2t)k r(t(s)) ="

answer

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

Step-by-step explanation:

The step by step procedure is to first determine the differentiate the given vector function

r(t) = 3ti + (1 - 4t)j + (1 + 2t)k

$\frac{d(r(t) = 3ti + (1 - 4t)j + (1 + 2t)k)}{dt} \\r'(t)=3i-4j+2k\\$

since s(t) is the arc length for r(t), which is define as

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt$

if we substitute the value of r'(t) we arrive at

$s(t)=\int\limits^t_0 {||r'(t)||} \, dt\\s(t)=\int\limits^t_0 {\sqrt{3^{2} +4^{2}+2^{2}} \, dt\\s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\$

$s(t)=\int\limits^t_ 0{\sqrt{29} } \, dx\\\\s(t)=\sqrt{29} t\\hence \\t(s)=\frac{s}{\sqrt{29} }$

substituting the value of t in to the given vector equation we have

$r(t(s)) = \frac{3s}{\sqrt{29} } i + (1 -\frac{4s}{\sqrt{29} }t)j + (1 + \frac{2s}{\sqrt{29} })k$

4 0

4 years ago

Josh says that (4)(-7)(-1) is equal to (4)(7). Evangelina says (4)(-7)(-1) is

Vadim26 [7]

Answer:

Evangelina and Josh can be considered correct but this can be simplified to just 28. so if you want the simplification of this problem it would be no one but both are correct if you just want to see if they equal the same answer

Step-by-step explanation:

they are correct because they could simplify it

7 0

3 years ago

Help please! 10 points!

____ [38]

Answer:

cos=adjacent/hyp

sin=opp/hyp

tan=opp/adjacent

8 0

3 years ago