Answer: Yes
Step-by-step explanation:
To solve this, imagine you have a vertical line. You can use a ruler or something straight. Move the ruler across the screen. Does the ruler intersect 2 points at once? If so, then it is not a function. If it only intersects one point, then it is a function.
Always remember: a function cannot have two x's with different y-values.
Hope that helped!
Step-by-step explanation:
Standard form is ax^2 + bx + c. Vertex form is a(x-h)^2 + k, which reveals the vertex and axis of symmetry. Factored form is a(x-r)(x-s), which reveals the roots.
Answer:
The first term is 3. The common difference is 2.
Step-by-step explanation:
The first term is x.
The common difference is d.
The second term is x + d.
3rd term: x + 2d
4th term: x + 3d
7th term: x + 6d
"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"
x + 3d = 3 * x Eq. 1
"the seventh term exceeds twice the third term by 1"
x + 6d = 2(x + 2d) + 1 Eq. 2
Simplify Eq. 1:
2x = 3d
Simplify Eq. 2:
x + 6d = 2x + 4d + 1
x = 2d - 1
Multiply both sides of the last equation by 2.
2x = 4d - 2
2x = 3d (simplified Eq. 1)
Since 2x = 2x, then the right sides are equal.
3d = 4d - 2
d = 2
2x = 3d
2x = 3(2)
2x = 6
x = 3
Answer: The first term is 3. The common difference is 2.
You should get it now from my previous answer.
But to apply it.
9 - 8b + 6b
9 + (-8b + 6b) <- Collect like bases (b)
9 + (-2b)
9 - 2b
Therefore it simplified is 9 - 2b
For this case we have that by definition, the domain of a function, is given for all the values for which the function is defined.
We have:
The given function is not defined when the denominator is equal to zero. That is to say:
To find the roots we factor, we look for two numbers that when multiplied give as a result "8" and when added as a result "-6". These numbers are:
Thus, the factored polynomial is:
That is to say:
Makes the denominator of the function 0.
Then the domain is given by:
All real numbers, except 2 and 4.
Answer:
x |x≠2,4
