What is an easier way to solve algebraic expressions?
1 answer:
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B = amount of students who chose Bulldog
n = amount of students who chose lion
t = amount of students who chose tiger
so.. "t" chose tiger, ok
"<span>Four times as many students chose Bulldog as chose Tiger"
namely, if "t" chose tiger, then 4 times that many chose Bulldog, thus
b = 4t
"</span><span>Twice as many students chose Lion as chose Tiger"
namely, if "t" students chose tiger, twice as many chose lion
n = 2t
now, we know a total of 273 students were surveyed, thus
</span>
<span>
</span>
n = amount of students who chose lion
t = amount of students who chose tiger
so.. "t" chose tiger, ok
"<span>Four times as many students chose Bulldog as chose Tiger"
namely, if "t" chose tiger, then 4 times that many chose Bulldog, thus
b = 4t
"</span><span>Twice as many students chose Lion as chose Tiger"
namely, if "t" students chose tiger, twice as many chose lion
n = 2t
now, we know a total of 273 students were surveyed, thus
</span>
</span>