Answer:
72°
Step-by-step explanation:
Given
Zy = 108°
Zx = ?
We know
Zx + Zy = 180° {being supplementary angles }
Zx + 108° = 180°
Zx = 180° - 108°
Zx = 72°
Hope it will help :)
Answer:
Step-by-step explanation:
The standard way of writing equation of a line in a point-slope form is as given;
y - y0 = m(x-x0)
m is the slope of the line
(x0,y0) is a point on the line.
Given the point (-2,-6), in order to determine with of the equation that correctly uses the point, we will substitute the point into the formula and get the necessary equation.
y - y0 = m(x-x0)
y - (-6) = m(x-(-2))
y+6 = m(x+2)
Since we are not given the slope, let's assume the slope is 5/2
The equation becomes y+6 =5/2(x+2). Option D is correct
Answer:
Step-by-step explanation:
Year on is 480 dollars and year two is 960 dollars
Answer:
9
Step-by-step explanation: did it
Hello there! Thank you for asking your question here at Brainly. I will be assisting you today with how to handle this problem, and will teach you how to handle it on your own in the future.
First, let's evaluate the question.
"The circumference of a circle is 6.28. What is the area of a circle?"
Now, let's remember the different formulas for area and circumference.
The circumference is "2•3.14•r", while the area is "3.14•r•r".
We have our circumference, 6.28.
However, we are looking for the area. Since we have the circumference, we need to narrow down to the radius (so we can solve for the area).
Let's set this up as an equation;
C = 2 • 3.14 • r
Plug in the value for our circumference.
6.28 = 2 • 3.14 • r
Multiply 2 by 3.14 and r to simplify the right side of the equation.
2 • 3.14 • r = 6.28 • r = 6.28r
We're now left with:
6.28 = 6.28r
Divide both sides by 6.28 to solve for r.
6.28 / 6.28 = 1
6.28r / 6.28 = r
We are now left with the radius:
R = 1.
Now, we can solve for the area.
Remember our formula for the area.
A = r • r • 3.14.
Plug in 1 for r.
A = 1 • 1 • 3.14
A = 3.14.
Your area is 3.14 units^2.
I hope this helps, and has prepared you for your future problems in relation to this topic!
