Question

AB formed by (-2,13) and (0,3) CD formed by (-5,0) and (10,3)

Answer 1

The measure of line AB is 10.2 units.

The measure of line CD is 15.3 units.

Step-by-step explanation:

Given that,

• The line AB is formed by the points (-2,13) and (0,3).
• The line CD is formed by the points (-5,0) and (10,3).

To find the distance of AB and CD, the distance formula is used.

Distance = $\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

To find the length of AB :

The points (-2,13) = (x1,y1) and (0,3) = (x2,y2)

Distance AB = $\sqrt{(0+2)^{2}+(3-13)^{2} }$

⇒ $\sqrt{(2)^{2} + (-10)^{2} }$

⇒ $\sqrt{4+100}$

⇒ $\sqrt{104}$

⇒ 10.2

The measure of line AB is 10.2 units.

To find the length of CD :

The points (-5,0) = (x1,y1) and (10,3) = (x2,y2)

Distance CD = $\sqrt{(10+5)^{2} + (3-0)^{2} }$

⇒ $\sqrt{(15)^{2} + (3)^{2} }$

⇒ $\sqrt{225 + 9}$

⇒ $\sqrt{234}$

⇒ 15.3

The measure of line CD is 15.3 units.