Remark
The proof is only true if m and n are equal. Make it more general.
m = 2k
n = 2v
m + n = 2k + 2v = 2(k + v).
k and v can be equal but many times they are not. From that simple equation you cannot do anything for sure but divide by 2.
There are 4 combinations
m is divisible by 4 and n is not. The result will not be divisible by 4.
m is not divisible by 4 but n is. The result will not be divisible by 4.
But are divisible by 4 then the sum will be as well. Here's the really odd result
If both are even and not divisible by 4 then their sum is divisible by 4
Using the confidence interval, it is found that the correct option is:
There is convincing evidence because the entire interval is above 0.
<h3>When does a confidence interval for the difference of proportions gives convincing evidence that there is a difference?</h3>
It gives convincing evidence when 0 is not part of the confidence interval.
In this problem, the interval is (0.02, 0.38), which does not contain 0, hence the correct option is:
There is convincing evidence because the entire interval is above 0.
More can be learned about confidence intervals at brainly.com/question/25890103
Answer:
(x+5^3 is the answer of this question
Step-by-step explanation:
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Answer: B
I think......
Step-by-step explanation:
