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svet-max [94.6K]
3 years ago
7

The function g(x) is a transformation of the cube root parent function,

Mathematics
1 answer:
Bad White [126]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Apex

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The elevation of the surface of the dead sea is _424.3 meters. in 2005 , the height of mt. everest was 8,844.43 meters. how much
Delicious77 [7]
We have the following statements:
 surface of the dead sea is 424.3 meters
 the height of mt. everest was 8,844.43 meters
 Therefore, the difference between both will be
 8844.43 - 424.3 = 8420.13 meters
 Answer
 
mt. everest was 8420.13 meters higher
5 0
3 years ago
One side of a rectangle is 3 m more than the other. If the perimeter of the rectangle is 30 m, what are its dimensions? *
uranmaximum [27]

Answer:

the length— 6

width— is 9

Step-by-step explanation:

you said One side— 3m MORE

so we will consider the length Number as X

we will consider width As three plus X

- You want to know the Perimeter. So we have to

add.

— so the expression is 3+3+x+x+x+x = 30

it is then simplified to 6+4x= 30

then we should be able to find out the X  which is 6

when we substitute the values with dimensions, you will get

your final Answer

I hope This Helped!

6 0
3 years ago
Pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeee help mwah. will give brainliest
Vadim26 [7]

Answer:

its 0.4 :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I need help with pre calculus.
otez555 [7]

Question 1

<h3>Answer:  Choice A) -7</h3>

-----------------

Explanation:

To compute f(g(2)), we'll first need to find g(2).

Locate 2 in the x row. Then read straight down until you get to the g(x) row. You should find that g(2) = 4

This means f(g(2)) becomes f(4). We then repeat the same process as before. Locate 4 in the x row, read straight down til you get to the f(x) row to find that f(4) =  -9

Overall, we can say f(g(2)) = -9

We do the same set of steps to compute g(f(-1)). You should find that f(-1) = -1 and g(f(-1)) = g(-1) = -2

Lastly, we subtract the results we got:  

f(g(2)) - g(f(-1)) = -9 - (-2) = -9+2 = -7

==============================================

Question 2

<h3>Answer: Choice B)  0</h3>

-----------------

Explanation:

If you were to graph each equation, you should get what you see below.

The red and blue curves do not intersect in any way. We need an intersection point to have a solution. Because there are no intersections, we don't have any solutions. The system is considered inconsistent.

==============================================

Question 3

<h3>Answer: Choice B</h3><h3>-2x^2+250x-2000</h3>

-----------------

Explanation:

x = number of scooters made and sold

Each scooter costs $150 to make. If you made x of them, then it costs 150x dollars. Then tack on the fixed cost of $2000 to get the expression 150x+2000

The cost function is C(x) = 150x+2000. We'll subtract this from the revenue function R(x) to get the profit P(x)

\text{Profit} = \text{Revenue} - \text{Cost}\\\\P(x) = R(x) - C(x)\\\\P(x) = (400x-2x^2) - (150x+2000)\\\\P(x) = 400x-2x^2-150x-2000\\\\P(x) = -2x^2+250x-2000\\\\

==============================================

Question 4

<h3>Answer: Choice B</h3>

\left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}

-----------------

Explanation:

g(x) = \frac{1}{x+1}\\\\g(f(x)) = \frac{1}{f(x)+1}\\\\g(f(x)) = \frac{1}{x^2+x-3+1}\\\\g(f(x)) = \frac{1}{x^2+x-2}\\\\g(f(x)) = \frac{1}{(x+2)(x-1)}\\\\(g\circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\

I started with the outer function g(x) and replaced each x with f(x) in the second step. Then I plugged in f(x) = x^2+x-3 and simplified. Factoring the denominator is helpful to determine where the denominator becomes zero. Specifically, it happens when x = -2 and x = 1. These x values must be kicked out of the domain to avoid a division by zero error.

So we start off with the real number line, and poke holes at x = -2 and x = 1.

The notation x \in \mathbb{R} means x is a real number. Then we tack on x \ne -2, x \ne 1

Overall, the domain is \left\{x\in \mathbb{R} \big| \ x \ne -2, x \ne 1\right\}

Let's see what happens if we tried plugging x = -1 into this composite function:

(g \circ f)(x) = \frac{1}{(x+2)(x-1)}\\\\(g \circ f)(-1) = \frac{1}{(-1+2)(-1-1)}\\\\(g \circ f)(-1) = \frac{1}{(1)(-2)}\\\\(g \circ f)(-1) = \frac{1}{-2}\\\\(g \circ f)(-1) = -0.5\\\\

We don't get a division by zero error, so x = -1 is allowed. The same can be said about any other x value as long as it's not -2 and not 1 either.

4 0
2 years ago
Please help me maths
Vsevolod [243]
V=lwh, so try to solve it that way.
4 0
4 years ago
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