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2 years ago

Which of the following statements about sets of numbers is true? (1 point)

Mathematics

2 answers:

gayaneshka [121]2 years ago

7 0

Answer:

-All integers are whole numbers.

-All rational numbers are natural numbers.

Step-by-step explanation:

Mamont248 [21]2 years ago

7 0

1:b

2:b

3:a

4:b

5:c

sums of real numbers quick check^

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In the geometric sequence below, what is the common ratio?<br><br> Sequence: 64,16,4,1

Elanso [62]

9514 1404 393

Answer:

1/4

Step-by-step explanation:

The common ratio is the ratio of successive terms:

16/64 = 4/16 = 1/4

The common ratio is 1/4.

4 0

2 years ago

What is the sum of the arithmetic series: s10 = -20, d = 4, a1 =?

Otrada [13]

<h2>Step-by-step explanation:</h2><h3> $\green\star$ Given</h3>

$\blue\star$ s10 = -20

$\blue\star$ n = 10

$\blue\star$ an = -20

$\green\star$ solution

$\green\star$ s10 = n\2 [a+(n-1)d]

$\green\star$ -20 = 10a2[a+(10-1)4]

$\green\star$ -4 = a +36

$\green\star$ a1 = -40

$\small\boxed{a = -40}$

Hope it helps.

Hope it helps

8 0

3 years ago

Read 2 more answers

Evaluate 8^<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B3%7D" id="TexFormula1" title="\frac{5}{3}" alt="\frac{5}{3}" align

almond37 [142]

Answer:

Step-by-step explanation:

32 is the correct answer

6 0

2 years ago

Read 2 more answers

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

2 years ago

What is -34 1/2 - 5 1/2

Verizon [17]

The answer is -40 because if you get rid of the negative sign and add instead of subtract... you get 40 so its like adding in the opposite direction.

3 0

3 years ago

Read 2 more answers