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Alex787 [66]
2 years ago
10

What comes after hit or miss? Song

Mathematics
2 answers:
Mice21 [21]2 years ago
7 0

Answer:

i guess they never miss, huh

you got a boyfriend i bet he doesn't kiss ya

Step-by-step explanation:

thats how it goes lol

musickatia [10]2 years ago
6 0

Answer:

Step-by-step explanation:

I guess they never miss huh

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Answer:

idk but go dtep by step

Step-by-step explanation:

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Directions - For the following problem, write a paragraph proof to justify each step you make. All work must be neat,
nlexa [21]

$ PS = \frac{4}{3} x

Solution:

Given PRQ is a triangle.

ST is a line parallel to RQ.

$PT = x, \ PQ = 3x,  \ SR=\frac{8}{3}x

TQ=PQ-PT

TQ=3x -x=2x

<u>Triangle proportionality theorem,</u>

<em>If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.</em>

$\frac{PS}{SR} =\frac{PT}{TQ}

$\frac{PS}{\frac{8}{3} x} =\frac{x}{2x}

Do cross multiplication, we get

$ PS \times 2x=x \times \frac{8}{3} x

Divide by 2x on both sides, we get

$ PS = \frac{4}{3} x

4 0
2 years ago
Which of the following activities are examples of data gathering? Check all that apply. A. Surveying students about their favori
katrin [286]
A. Surveying the students about their favorite type of math problem.
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2 years ago
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Which expressions are equivalent to g + h + (j + k)? Check all that apply.
Paha777 [63]

Answer:

3.

{ \tt{g + h + (j + k)}} \\  = (g + h) + j + k

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2 years ago
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Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

 f(x) = x^2 + 3x interval: [-2, 3]:
 f(-2) = x^2 + 3x  = (-2)^2 + 3(-2) = 4 - 6 = -2&#10;&#10;f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
 AVR = \frac{-20}{-5}
 AVR = 4

 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
 f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15&#10;&#10;f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
 AVR = -1

 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4&#10;&#10;f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
5 0
3 years ago
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