We are given the equation:
DA - 2qA = B³
Taking 'A' common on the LHS
A(D - 2q) = B³
Dividing both sides by (D - 2q)
A = B³ / (D - 2q)
the correct answer is 36°
Given:
The length of the ladder = 12 ft
The angle of ladder with ground = 60 degrees
To find:
How far up the building the ladder will reach.
Solution:
Using the given information draw a figure as shown below.
We need to find the vertical distance between the top of ladder and the ground.
Let x be the required distance.
In a right angle triangle,

In the below triangle ABC,



Multiply both sides by 12.


Therefore, the ladder will reach
ft far up the building.
Answer:
The answer to the question on the gradient between points
(8,6) and (10,12)
Is 3
Step-by-step explanation:
Given data
For the points (8,6) and (10,12).
X1= 8
Y1=6
X2=10
Y2=12
We know that the gradient between two points is expressed as
M= ΔY/ΔX
M= (Y2-Y1)/(X2-X1)
M= (12-6)/(10-8)
M= 6/2
M= 3