Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
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- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811
Answer:
I think you would multiply 20 × 4 and the answer would be 80 that the scientist counted the number of plants in each 4 sections after 20 days.
Log₄(y+2) = 3, transform it into exponent form:
(y+2) = 4³
y+2 = 64
y= 62
Answer: all true
Step-by-step explanation:
Look at the picture closely ull see it
Area of a semicircle is 1/2* πr^2
Area of a square is s^2
Square’s area: 4mm^2
The radius is 3mm
Plug into the equation
1/2* π(3^2)
1/2* π(9)
We can use 3.14 as an estimate of pi
1/2*28.26
14.13mm^2
Now just add them both
Total area 18.13mm^2
