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3 years ago

10. Mr. Ward bought a used car forx dollars. One year later the value of the car was 0.72x. Which

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

7 0

Answer:

Step-by-step explanation:

0.72 = 72%

So that being the case, his car's value decreased by 72%

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−24 = −0.6k can you slove this answer

Kruka [31]

Answer:

-24 = -0.6k

k=-24/-0.6

k=40

Let me know if this helps!

5 0

2 years ago

Eric ordered 6 tacos and 1 large pop. The large pop costs $2.00 and the total cost of his order was

pshichka [43]

Answer: 6x + $2= $21.50

Step-by-step explanation:

To make an equation first we are going to give the cost of each taco the variable x since we don't know what it is. Then we will combine 6 multiplied by x to get 6x and add it to $2 to get $21.50 so the equation will be 6x + $2= $21.50. First we subtract 2 from both sides of the equation which makes the equation become 6x= $19.50. Then we divide both sides of the equation by 6 and get x=$3.25. This means that each taco cost $3.25.

5 0

3 years ago

Manuel rented a truck for one day. There was a base fee of $14.95, and there was an additional charge of 87 cents for each mile

sp2606 [1]

base fee 14.95

0.87 cents per mile

total =248.98

248.98-14.95 = 234.03

234.03/0.87 =269 miles

7 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²