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Sati [7]
3 years ago
13

if two fractions have the same denominator but different new Mary which fraction is greater? Give an example

Mathematics
1 answer:
german3 years ago
5 0
It would be the one with the greater numerator 6/6 would be greater than 5/6
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A sphere with radius r and a cylinder with radius r and a height of r are shown below. How do the surface areas of these solid f
AnnyKZ [126]

Answer:

  • The surface area of the sphere in terms of r is 4πr^2 square units.
  • The surface area of the cylinder in terms of r is 4πr^2 square units.
  • The surface area of the cylinder and sphere are the same.

Step-by-step explanation:

The surface area of the sphere is given by the formula ...

  A = 4πr^2

The surface area of the cylinder is given by the formula ...

  A = 2πr^2 +2πrh

Here, the height (h) is equal to r, so this simplifies to ...

  A = 2πr^2 +2πr·r = 4πr^2 . . . . . the same area as the sphere

7 0
3 years ago
Read 2 more answers
Please help asap will mark brainliest
Dovator [93]

Answer:

The fraction is 7/10 and the decimal is 0.7

Step-by-step explanation:

Each incriment represents 1/10, or 0.1.

7 0
3 years ago
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Cost of meal for 3 at Olive Garden Restaurant with the tax is $54.
Lynna [10]
It should be 8 dollars
3 0
2 years ago
Helppppppppppp meeeeeeeeeee
kozerog [31]

Answer:

It's 11.72

Step-by-step explanation:

Area=)1/2×15/4×25/4

Answer》11.72

Hope it helps...

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3 0
3 years ago
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1. Contaminated water is subjected to a cleaning process. The concentration of the
Leokris [45]

Answer:

The concentration of pollutants in the water can be defined as the quotient between the mass of pollutants and the total mass of water.

Assuming that 1L of water weighs 1000 grams, we know that:

Mass of pollutants = 5mg = 0.005g.

Initial concentration = 0.005g/1000g = 0.000005

If we multiply this by 100%, we get the percentage:

0.000005*100% = 0.0005%

Now, the mass of pollutants decreases by 10% each hour.

So if initially, we have 5mg

After one hour, we will have: 5mg - 0.1*5mg = 5mg*(0.9).

After another hour, we will have: 5mg*(0.9) - 0.1*5mg*0.9 = 5mg*(0.9)^2.

And so on, then after n hours, the mass of pollutants will be:

M(n) = 5mg*(0.9)^n

Or we can write this in grams as:

M(n) = 0.005g*(0.9)^n

Then the concentration as a function of time in hours will be:

C(n) = M(n)/1000g = (0.005g/1000g)*(0.9)^n

Notice that the thing between the parentheses is the initial concentration, then if we write this in percentage form:

c(n) = 100%*(0.005g/1000g)*(0.9)^n = 0.0005%*(0.9)

The function that represents the concentration of polution in the water as a function of hours is:

c(n) = 0.0005%*(0.9)

6 0
3 years ago
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