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3 years ago

What is Two thirds of four forths-fifths of a dozen

Mathematics

1 answer:

Natali [406]3 years ago

4 0

Answer:

2/3 x 4/5 = 8/15

Step-by-step explanation:

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Answer:

$n=(\frac{2.17(0.143)}{0.023})^2 =182.03 \approx 183$

So the answer for this case would be n=183 rounded up to the nearest integer

Step-by-step explanation:

Information provided

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma = 0.143$ represent the population standard deviation

n represent the sample size

$ME = 0.023$ the margin of error desired

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.023 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence level is 97% or 0.97 and the significance would be $\alpha=1-0.97=0.03$ and $\alpha/2 = 0.015$ then the critical value would be: $z_{\alpha/2}=2.17$ , replacing into formula (5) we got:

$n=(\frac{2.17(0.143)}{0.023})^2 =182.03 \approx 183$

So the answer for this case would be n=183 rounded up to the nearest integer

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