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max2010maxim [7]
3 years ago
13

Please help me sole this equation !!

Mathematics
2 answers:
tester [92]3 years ago
6 0
(9x-15)/4=x /*4...... 9x-15=4x........ 5x=15........ x=3
Mnenie [13.5K]3 years ago
5 0
\frac{9x - 15}{4} = x             / * 4 (both sides)
9x - 15 = 4x                          / - 9x (both sides)
-15 = -5x                              / ÷ (-5) (both sides)
x = 3
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In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti
elena-14-01-66 [18.8K]

Answer:

a)

y = 0.3035 + 0.0082x

b)

0.6315 mm

c)

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}

Replacing the values in our formula (we will round at the end of the calculations)

\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476

the Y-intercept b is computed with the formula

\bf b=\bar y-m\bar x

therefore we have

\bf b=0.5188-0.008169476*26.36=0.303452613

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

 

x = 23.9634 °C

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I’m confused on the type of angles these are and how to solve them . (Parallel lines and Transversals)
svp [43]

Answer:

7) 49°

8) 77°

9) 87°

10) 135°

Step-by-step explanation:

7) The angles are between the parallel lines, so are "interior." They are on opposite sides of the transversal, so are "opposite interior" angles. Such angles are congruent, so ...

... ? ≅ 49°

8) The angles are adjacent interior angles, so are supplementary.

... ? + 103° = 180°

... ? = 77°

9) The angles are outside the parallel lines, so are "exterior." They are on opposite sides of the transversal, so are "opposite exterior" angles. Such angles are congruent.

... ? ≅ 87°

10) These are vertical angles, so are congruent. (The other parallel line is irrelevant and doesn't need to be there for this relationship to be true.)

... ? ≅ 135°

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