Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
1) Given
2) m∠1 + m∠2 = 90°
3) BD bisects ∠ADC
4) definition of angle bisector
5) definition of congruency
6) m∠1 + m∠3 = 90°
7) ∠1 is complementary to ∠3 (7) definition of complementary
If there is a drop down box, and my answer is not an option, type in the options in the comment box and I will let you know which theorems (or definitions) are the same as my answer.
Answer:27/343 or 0.0787172
Step-by-step explanation:
First you need to place the exponent on both the numerator and the demonimator to make 3 to the power of 3 over 7 to the power of 3
Next you evaluate the numerator so 3 to the power of 3 is 27
and 7 to the power of 3 is 343 so your answer in fraction form is 27/343
you can also change into a decimal if you divide the fraction if you need to
Hope this helps
Diagonal angles have the same measure - not sure what u mean by oposite.
The correct answer is √313. ( square root of 313 or 17.7)
Hope this helps.
