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3 years ago

13

Solve for the following variables

1 answer:

fgiga [73]3 years ago

8 0

Answer: not 100 percent sure but i think x=37 z=110 y=33

Step-by-step explanation:

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You take a three-question true or false quiz. You guess on all the questions. What is the probability that you will get a perfec

prisoha [69]

It would be 1/8. 2 to the third is 8, and all three answers correct is one option.

4 0

3 years ago

Read 2 more answers

What number is 150 more than the product of 5 and<br> 4892

Serjik [45]

The number that is 150 more than the product of 5 and 4892 is 24700

7 0

2 years ago

Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2

kifflom [539]

Answer:

The solution of the differential equation is $y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

<u>i) Using characteristic equation:</u>

The characteristic equation method assumes that y(t)= $e^{rt}$ , where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

$y'=re^{rt}$

$y"=r^{2}e^{rt}$

$r^{2}e^{rt}+e^{rt}=0$

$(r^{2}+1)e^{rt}=0$

As $e^{rt}$ could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

$y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}$

Using Euler's formula:

$y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]$

$y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)$

$y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)$

The particular solution of the differential equation is given by:

$y(t)_{p}=ASin(2t)+BCos(2t)$

$y'(t)_{p}=2ACos(2t)-2BSin(2t)$

$y''(t)_{p}=-4ASin(2t)-4BCos(2t)$

So we use these derivatives in the differential equation:

$-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)$

$-3ASin(2t)-3BCos(2t)=Sin(2t)$

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

$y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)$

Using the initial conditions we can check that C1=5/3 and C2=2

<u>ii) Using Laplace Transform:</u>

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]= $\frac{2}{(s^{2}+4)}$

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) = $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)-2s-1= $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)= $\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}$

Y(s)= $\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}$

Y(s)= $\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}$

Using partial franction method:

$\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}$

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)= $\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}$

Y(s)= $-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}$

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[ $-\frac{1}{3} \frac{2}{s^{2}+4}$ ]-ℒ⁻¹[ $2\frac{s }{s^{2}+1}$ ]+ℒ⁻¹[ $\frac{5}{3}\frac{1}{s^{2}+1}$ ]

$y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

3 0

3 years ago

Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,

xeze [42]

Answer:

D. $x-\frac{5}{2}y = \frac{25}{2}$

Step-by-step explanation:

Given

$y = \frac{2}{5}x - 5$

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

$x - \frac{5}{2}y = \frac{25}{2}$

This is shown as follows;

$y = \frac{2}{5}x - 5$

Multiply both sides by $\frac{5}{2}$

$\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)$

Open Bracket

$\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5$

$\frac{5}{2}y = x - \frac{25}{2}$

Subtract x from both sides

$\frac{5}{2}y - x = x -x - \frac{25}{2}$

$\frac{5}{2}y - x = - \frac{25}{2}$

Multiply both sides by -1

$-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1$

$-\frac{5}{2}y + x = \frac{25}{2}$

Reorder

$x-\frac{5}{2}y = \frac{25}{2}$

<em>Hence, the correct option is D</em>

$x-\frac{5}{2}y = \frac{25}{2}$

9 0

2 years ago

Read 2 more answers

Evaluate 1.80/Y for y= 0.009 express your answer is in simplest form.

igomit [66]

Evaluate 1.80/Y for y= 0.009

We replace 0.009 for y

So fraction becomes $\frac{1.80}{0.009}$

Now , to simplify the fraction we try to remove the decimal from denominator

0.009 have three digits after the decimal point, so we multiply by 1000 to remove the decimal point. Multiply top and bottom by 1000 to make equivalent fraction.

$\frac{1.80*1000}{0.009*1000}$

$\frac{1800}{9}$ = 200

Answer is 200

3 0

3 years ago