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Sholpan [36]
3 years ago
10

5 1/2+ 3 2/3+ 1 4/5

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

10\frac{29}{30}

Step-by-step explanation:

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5}

Let us group the integers and the fractions.

5\frac{1}{2} +3\frac{2}{3} +1\frac{4}{5} = (5+3+1)+(\frac{1}{2} +\frac{2}{3}+\frac{4}{5}  )

= 9+\frac{15+20+24}{30}

= 9+\frac{59}{30}

=9+1\frac{29}{30}

=10\frac{29}{30}

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Answer:

Actually, what you said you have so far is not correct.  The 2 correct answers are the 1st one (x + y = 15) and the 5th one (15x + 10y > 180)

Step-by-step explanation:

If tutoring French is x hours and scooping ice cream is y hours and he is going to work 15 hours for sure doing both, then we can add them together to get that x hours + y hours = 15 hours, or put simply:  x + y = 15.

Now we are going to throw in the added fun of the money he makes doing each.  The thing to realize here is that we can only add like terms.  So looking at the equation above, we have x hours of tutoring and y hours of scooping, so if we want to add them, we will add those number of hours together to get the total number of hours he worked, which we know to be 15.  The same goes for money.  If we add money earned from tutoring to money earned from scooping, we need that to be greater than the money he wants to earn which is 180 at least.  Because he wants to earn MORE than $180. we use the ">" sign.  Since he earns $15 an hour tutoring, that expression is $15x; since he earns $10 an hour scooping, that expression is $10y.  Now add them together (and you CAN because they are both expressions relating dollars to dollars) and set the sum > $180:

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3 years ago
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Hello a value is missing in your question below is the value

samples of n = 10

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therefore at  94.87% confidence interval the estimated population mean is

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