Question

Given: x - 6 1/3≤ 1 1/2 Choose the solution set. a. {x | x ∈ R, x ≤ 7 5/6} b. {x | x ∈ R, x ≤ 7 2/5} c. {x | x ∈ R, x ≤ 5 1/6}

Answer 1

$x-6\frac{1}3\leq1\frac{1}2$

Add 6 1/3 to each side.

$x\leq1\frac{1}2+6\frac{1}3$

To add together the 1/2 and the 1/3, change them to a common denominator.

$x\leq1\frac{3}6+6\frac{2}6$

$x\leq7\frac{5}6$

$\boxed{\{\ x\ |\ x\in\mathbb{R},\ x\leq7\frac{5}6\}}$