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Hoochie [10]
3 years ago
8

Solve the system by substitution.

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0
As we know y=3/4x-3
Let's put it in the second equation
3/4x-3=1/4x+1
3/4 x -1/4 x = 1+3
2/4 x = 4
X= 4*4/2
x=8
Put x= 8 in first equation
y= 3/4 *8 -3
y=6-3
y=3
Check the answer
3=3/4 *8 -3
3=6-3
3=3
Correct
So(y, x) = (3,8)
Because x=8 and y=3
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Calculeaza<br>2+(8-6)=<br>(9-7)+5=<br>10-(1+8)=<br>(3+7)-9=<br>(1+2+3)-5=<br>10-(2+3+4)=​
Alex787 [66]

Answer:

1. 2+(8-6)= 4

2+2=4

2. (9-7)+5= 7

2+5=7

3. 10-(1+8)= 1

10-9=1

4. (3+7)-9= 1

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5. (1+2+3)-5= 1

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2 years ago
PLEASE HELP! 10 POINTS!
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7 0
3 years ago
g Consider the experiment of a single roll of an honest die and a single toss of 3 fair coins. Let X be the value on the die and
klemol [59]

Answer:

The probability function of X and Y is

P(X = k, Y = 0)  = 1/48\\P(X = k, Y = 1) = 1/16\\P(X = k, Y = 2) = 1/16\\P(X = k, Y = 3) = 1/48

With k in {1,2,3,4,5,6}

Step-by-step explanation:

We can naturally assume that X and Y are independent. Because of that, P(X=a, Y=b) = P(X=a) * P(Y=b) for any a, b.

Note that, since the die is honest, then P(X=k) = 1/6 for any k in {1,2,3,4,5,6}. We can conclude as a consequence that P(X=k, Y=l) = P(Y=l)/6 for any k in {1,2,3,4,5,6}.

Y has a binomial distribution, with parameters n = 3, p = 1/2. Y has range {0,1,2,3}. Lets compute the probability mass function of Y:

P_Y(0) = {3 \choose 0} * 0.5^3 = 1/8

P_Y(1) = {3 \choose 1} * 0.5* 0.5^2 = 3/8

P_Y(2) = {3 \choose 2} * 0.5^2*0.5 = 3/8

P_Y(3) = {3 \choose 3} * 0.5^3 = 1/8

Thus, we can conclude that the joint probability function is given by the following formula

P(X = k, Y = 0) = 1/8 * 1/6 = 1/48\\P(X = k, Y = 1) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 2) = 3/8 * 1/6 = 1/16\\P(X = k, Y = 3) = 1/8 * 1/6 = 1/48

For any k in {0,1,2,3,4,5,6}

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3 years ago
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Answer:

A = 24 cm^2

Step-by-step explanation:

The area of a triangle is given by

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A = 1/2 (12)*4

A = 24 cm^2

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3 years ago
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