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Yuliya22 [10]
3 years ago
6

A certain substance X has a normal boiling point of 134.5°C and a molal boiling point elevation constant =Kb1.36·°C·kgmol−1 . Ca

lculate the boiling point of a solution made of 76.g of urea NH22CO dissolved in 850.g of X . Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
erastova [34]3 years ago
3 0

Answer:

136.5°C

Explanation:

Given data

  • Boiling point of X: 134.5°C
  • Molal boiling point elevation constant (Kb): 1.36·°C·kg.mol⁻¹

We can calculate the elevation in the boiling point (ΔT) using the following expression.

ΔT = Kb × m

where,

m is the molality

The molar mass of urea is 60.06 g/mol. The moles of urea corresponding to 76 g is:

76 g × (1 mol/60.06g) = 1.3 mol

The mass of the solvent (X) is 850 g = 0.850 kg.

The molality is:

m = 1.3 mol / 0.850 kg = 1.5 mol/kg

Then,

ΔT = Kb × m

ΔT = 1.36·°C·kg.mol⁻¹ × 1.5 mol/kg

ΔT = 2.0 °C

The boiling point of the solution is

134.5°C + 2.0°C = 136.5°C

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\displaystyle \Delta H = \frac{Q}{n} = \frac{5.4843\text{kJ}}{0.212162\;\text{mol}} = 25.8\;\text{kJ}\cdot\text{mol}^{-1}.

The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.

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