Answer: This means that the answer can be proven wrong.
Explanation:
Hope this helps!!
40.0mL(1 L/1000 mL) = 0.040 L
<span>then plug into the formula M = moles/liters </span>
<span>0.035 M = moles/ 0.040L </span>
<span>multipy both sides by 0.040L, and you get 0.0014 moles </span>
<span>so the answer is 1</span>
Answer:
Vol of 4 moles CO₂(g) at STP = 89.6 Liters
Explanation:
STP
P = 1 Atm
V =
T = 0°C = 273 K
n = 4 moles
R = 0.08206 L·Atm/mol·K
Using Ideal Gas Law PV = nRT => V = nRT/P
V = (4 moles)(0.08206 L·Atm/mol·K)(273 K)/(1 Atm) = 89.6 Liters
For one mole of hydrogen, H, the atomic mass is 1 g per mole. Hydrogen contains 1 proton and zero neuton. A neutral atom of hydrigen also contains 1 electron.
Answer:
Kc = 1.09x10⁻⁴
Explanation:
<em>HF = 1.62g</em>
<em>H₂O = 516g</em>
<em>F⁻ = 0.163g</em>
<em>H₃O⁺ = 0.110g</em>
<em />
To solve this question we need to find the moles of each reactant in order to solve the molar concentration of each reactan and replacing in the Kc expression. For the reaction, the Kc is:
Kc = [H₃O⁺] [F⁻] / [HF]
<em>Because Kc is defined as the ratio between concentrations of products over reactants powered to its reaction coefficient. Pure liquids as water are not taken into account in Kc expression:</em>
<em />
[H₃O⁺] = 0.110g * (1mol /19.01g) = 0.00579moles / 5.6L = 1.03x10⁻³M
[F⁻] = 0.163g * (1mol /19.0g) = 0.00858moles / 5.6L = 1.53x10⁻³M
[HF] = 1.62g * (1mol /20g) = 0.081moles / 5.6L = 0.0145M
Kc = [1.03x10⁻³M] [1.53x10⁻³M] / [0.0145M]
<h3>Kc = 1.09x10⁻⁴</h3>
