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defon
3 years ago
9

If chords are =, then arcs are =. If Arc BC = Arc DE, then BC = DE 2. If arcs are =, then chords are =. If AX is perpendicular t

o BC, then BX = XC 3. Diameters perpendicular to chords bisect the chord If BC = DE, then Arc BC = Arc DE

Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

The circle diagram for the representation is as shown in the diagram.

Step-by-step explanation:

The representation of the theorems is shown in the attachment.

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Solve this If you can​
ASHA 777 [7]

Answer:

I cannot solve this okay

4 0
3 years ago
5. Original Price: $40 Sale Price: $30
telo118 [61]
It’s %25 off think about it 40-10=30 and that’s %25 of it hope I help you have a good day
5 0
3 years ago
Write an equation perpendicular to x-3y=3 passes through (5,-9)
kherson [118]
3y=x-3
y=1/3x-1
Perpendicular slope: -3
y=-3x+b
Plug in the coordinates in the equation:
-9=-3(5)+b
-9=-15+b
4=b
Equation: y=-3x+4
Also, when finding the perpendicular slope you take the reciprocal of the original slope and make it negative if it is positive and make it positive if it’s negative.
8 0
3 years ago
1. Describe the relationship between the terms in the sequence 13, 26, 52,
Vilka [71]

Answer: All of the numbers in the sequence are going up twice the amount as before. The next three terms will be 208, 416, 832

4 0
2 years ago
Read 2 more answers
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

{x}^{2}  = 64 \\  \sqrt{ {x}^{2} }  =  \sqrt{64}  \\ x = 6

3 0
3 years ago
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