60 percent of 264
=(60/100)*264
= (60*264)/100
= 15840/100=158.4
Answer:
a)![s=\sqrt{1+d^2}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B1%2Bd%5E2%7D)
b)d(t)=500t
c)![s(t) =\sqrt{1+250000t^2}](https://tex.z-dn.net/?f=s%28t%29%20%3D%5Csqrt%7B1%2B250000t%5E2%7D)
Step-by-step explanation:
d = Horizontal distance
s = the distance between the plane and the radar station
The horizontal distance (d), the one mile altitude, and s form a right triangle.
So, use Pythagoras theorem
![Hypotenuse^2=Perpendicular^2+Base^2](https://tex.z-dn.net/?f=Hypotenuse%5E2%3DPerpendicular%5E2%2BBase%5E2)
![s^2=1^2+d^2](https://tex.z-dn.net/?f=s%5E2%3D1%5E2%2Bd%5E2)
a) ![s=\sqrt{1+d^2}](https://tex.z-dn.net/?f=s%3D%5Csqrt%7B1%2Bd%5E2%7D)
(b) Express d as a function of the time t (in hours) that the plane has flown.
![distance = speed \times time](https://tex.z-dn.net/?f=distance%20%3D%20speed%20%5Ctimes%20time)
d(t)=500t
(c) Use composition to express s as a function of t.
![s(t) =\sqrt{1+d^2}](https://tex.z-dn.net/?f=s%28t%29%20%3D%5Csqrt%7B1%2Bd%5E2%7D)
using b
![s(t) =\sqrt{1+(500t)^2}\\s(t) =\sqrt{1+250000t^2}](https://tex.z-dn.net/?f=s%28t%29%20%3D%5Csqrt%7B1%2B%28500t%29%5E2%7D%5C%5Cs%28t%29%20%3D%5Csqrt%7B1%2B250000t%5E2%7D)
2(2,1)(14,10)
(4,2) - (14,10)= (-10, -8)
The coordinates of K are (-10, -8).
Answer:
we should know that :
sin ( a + b ) = sin a * cos b + sin b cos a
For the given equation :
sin (π + q) = sin π * cos q + sin q * cos π
sin π = zero and cos π = -1
∴ sin (π + q) = 0 * cos q + sin q * (-1) = - sin q
<u>Another solution:</u>
The angle (π + q) lies in the third quarter ⇒ (1)
(π + q) and (-q) are supplementary angles ⇒ (2)
From (1) and (2)
sin(π + q) = -sin q
Answer:
1.25x10^2
Step-by-step explanation:
5x5^2
5x5x5=125
125=1.25x10^2
Therefore 5x5^2=1.25x10^2