B
sohcahtoa
cah
adjacent over hypotenuse
5/29
I think its 150 thats what i put and it said it was correct
<span>distance=6390km; time=9 hrs; rate=710kph
With the wind Data:
distance=5150km; time=5hrs; rate=1030kph
EQUATIONS:
airspeed+jetstream=1030
airspeed-jetstream=710
Subtract these equations to get:
2jetstream=320kph
jetstream=160mph </span>
Find the inverse, interchange the variables to solve for y
f-1 (x)=-
![\frac{8- \sqrt[]{_2(-8+x)} }{2} ,](https://tex.z-dn.net/?f=%20%5Cfrac%7B8-%20%5Csqrt%5B%5D%7B_2%28-8%2Bx%29%7D%20%7D%7B2%7D%20%2C)