Answer:
486
Step-by-step explanation:
just multiply and divide
8 x 27 / 4 x 9
The flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Given, f = x³i + y³j + z³k
we have to find the flux of the given function f = x³i + y³j + z³k
On partial differentiating the function, we get
f' = 3x²i + 3y²j + 3z²k
f' = 3(x²i + y²j + z²k)
So, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
Hence, the flux of the given function f = x³i + y³j + z³k is given by f',
f' = 3(x²i + y²j + z²k)
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Answer: The correct answer will be C. (Since the last comment got deleted smh)
-(q + 14) = -3 + (-14)
-q - 14 = -3 -14
-q - 14 = -11
-q = +14 - 11
-q= 3